A 434.5 g sample of water at 20.0 °C is mixed with 100.0 g of a certain metal at 95.0 °C. After thermal equilibrium was established, the temperature of the mixture is 24.6 °C. What is the specific heat capacity of the metal?

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 39PS: A piece of titanium metal with a mass of 20.8 g is heated in boiling water to 99.5 C and then...
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A 434.5 g sample of water at 20.0 °C is mixed with 100.0 g of a certain metal at 95.0 °C. After thermal equilibrium was established, the temperature of the mixture is 24.6 °C. What is the specific heat capacity of the metal?

Expert Solution
Introduction

to find Cp for this metal use this above ,

Heat lost by the metal = heat gained by the water

Given that,
mass of metal, mm = 100 g
mass of water, mw= 434.5 g
Initial temperature of water = T1 = 20o
Initial Ttemperature of the metal = T2 = 95o
Final temperature of water and metal = 24.6oC = T3
Cp for water = 4.184 J/goC  

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