A 6.25 kg block ice at 0 degrees Celsius is being warmed on a glass stove top. The thermal conductivity of the glass is 1.00 W/ (m K) and the glass is 0.50 cm thick. If the radiator plate underneath the glass raises the temperature of the bottom of the glass to 125 degrees Celsius, how long would it take to completely melt the ice? Assume the ice remains a solid rectangle with a square base of side 15 cm as it melts. B. What is the rate of entropy change in Joules/ Kelvin/ seconds of the melting ice?

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Asked Nov 26, 2019
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A 6.25 kg block ice at 0 degrees Celsius is being warmed on a glass stove top. The thermal conductivity of the glass is 1.00 W/ (m K) and the glass is 0.50 cm thick. If the radiator plate underneath the glass raises the temperature of the bottom of the glass to 125 degrees Celsius, how long would it take to completely melt the ice? Assume the ice remains a solid rectangle with a square base of side 15 cm as it melts.

 

B. What is the rate of entropy change in Joules/ Kelvin/ seconds of the melting ice?

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Step 1

The quantity of heat passing in time t is

КА(ДТ
о-
х
хо
КА(AT)
хтL
[2]
КА(АТ)
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Image Transcriptionclose

КА(ДТ о- х хо КА(AT) хтL [2] КА(АТ)

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Step 2

The time t is...

107m
0.50 cm x
(6.25kg)(333550J/kg)
cm
t =
10 m
(1W/m K 15cmx
(125K)
3706.11s
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107m 0.50 cm x (6.25kg)(333550J/kg) cm t = 10 m (1W/m K 15cmx (125K) 3706.11s

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Thermodynamics

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