Question
Asked Dec 25, 2019
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A 75-g ice cube at 0°C is placed in 825 g of water at 25°C. What is the final temperature of the mixture?

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Expert Answer

Step 1

The heat energy of water required to change the temperature is

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Qw =m„CwAT =m yCw (T, – T;)

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Step 2

Substituting the values gives

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Qy = (825g)(1.00cal'g - °C) (25°C-T) = 825.0( 25.0 – T) .(1)

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Step 3

The total heat energy gained...

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Q= Q +Q = mL; +m,c (T- T)

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Science

Physics

Thermodynamics

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