A ball is launched upward from a height 40 feet above ground level. The ball’s height at tseconds is given by ℎ(?) = −16?2 + 128? + 40. (SLO #1, 6)a. At what time(s) will the ball be at 100 feet? Show your work. Round answer(s) tothe nearest tenth.b. In your own words, explain what was happening with the flight of the ball at the time(s)that it was at 100 feet.

Question
Asked Dec 4, 2019
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A ball is launched upward from a height 40 feet above ground level. The ball’s height at t
seconds is given by ℎ(?) = −16?
2 + 128? + 40. (SLO #1, 6)
a. At what time(s) will the ball be at 100 feet? Show your work. Round answer(s) to
the nearest tenth.
b. In your own words, explain what was happening with the flight of the ball at the time(s)
that it was at 100 feet.

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Expert Answer

Step 1

a.

Determine the time at which the height of the ball will be 100 ft.

We have the height equation

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h(t)-16t128t +40, where the time t is in seconds

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Step 2

At h = 100, the equation becomes

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100 = -161? +1281 + 40 →-161 + 128t – 60 = 0

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Step 3

Solve the above equation using quadratic formula to find the values of t.

...

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128128-4-16)(-60) 2(-16) t -128 ±12544 -32 -128 112 -32 1 15 2 2 0.5,7.5

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