Question
Asked Dec 16, 2019
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A ball thrown straight up into the air is found to be moving at
1.50 m/s after rising 2.00 m above its release point. Find the
ball’s initial speed.

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Expert Answer

Step 1

Given,

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Height reached,h=2 m Speed,v = 1.50 m/s Acceleration due to gravity,g =-9.80 m/s?

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Step 2

As ball is going straight up so there will be acceleration due to gravity acting. Using Kinematics equation final speed of ball is calculated as follows,

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v² = v} +2gh v =v – 2gh Vv² – 2gh Vo =

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Step 3

By substituting the given ...

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Vo = v - 2gh V(1.50) – 2(-9.80)(2) Vo 1% = Vo = V2.25+ 39.2 Vo =V41.45 Vo = 6.44 m/s

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Tagged in

Science

Physics

Kinematics

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