Question
Asked Dec 19, 2019
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A ball thrown straight up into the air is found to be moving at 2.77 m/s after rising 1.69 m above its release point. Find the ball's initial speed (in m/s).
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m/s
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A ball thrown straight up into the air is found to be moving at 2.77 m/s after rising 1.69 m above its release point. Find the ball's initial speed (in m/s). HINT m/s

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Expert Answer

Step 1
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Given, Final velocity v = 2.77 m/s Height h=1.69 m

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Step 2
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By the Newton's equation of motion V = u² + 2ah The ball moving in upward direction and acceleration g is in downward direction. V = u +2(-g)h V = u - 2gh u = yv + 2gh

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By putting the values; V(2.77) +2×9.8×1.69 и%3D U = 7.6729+33.124 U = 6.38 m/s

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Physics

Kinematics

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