A beam whose centre of gravity divides it into two portions, a and b. is placed inside a smooth sphere; show that, if 0 be its inclination to the horizon in the position of equilibrium and 2a be the angle subtended by the beam at the centre of the sphere, thom b - a tan 0 tan a. b +a

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A: Solution is here

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A: Topic:- geometry

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A: As per our guidelines we can answer only three question.

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A: Topic:- algebra

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A: Given that the two planes: P1:2x-y+z=1P2:x+z=-3Normal   are,Let,      n^1:    2i-j+k=1n^2:   i+k=-3

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Q: thus. d the point on he sphere X+y?+=4 Selution:- ans.-

A: We use Lagrange Multiplayer method.

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A: Use property of tangent line and secant line

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A: Answer and explanation is given below..

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Q: A beam whose centre of gravity divides it into two portions, a and b. is placed insıde a smooth…

A: I am attaching image so that you understand each and every step.

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Q: A beam whose centre of gravity divides it into two portions, a and b, is placed insıde a smooth…

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Q: If ở x w = i- j+ k, and v · w = 4, and 0 is the angle between v and w, then (a) tan 0 (b) ө

A: (a)v×w =i-j+k|v×w| =12+(-1)2+12=3|v×w| =3|v×w| =|v| |w| sinθ →(1)now,v.w =|v| |w| cosθ →(2)(1)(2)⇒…

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Q: 4. JK, KL, and LJ are all tangent to cirele O1 JA = 13, AL = 12, and CK = 9. Find the perimeter of…

A: Triangles

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A: -81π/2