# A block of mass m = 2.50 kg is pushed d = 3.00 m along a frictionless horizontal table by a constant applied force of magnitude F = 18.0 N directed at an angle θ = 25.0° below the horizontal as shown in the figure below.A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle θ above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block. (a) Determine the work done by the applied force. (b) Determine the work done by the normal force exerted by the table. (c) Determine the work done by the force of gravity. (d) Determine the work done by the net force on the block.

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A block of mass

m = 2.50 kg

is pushed

d = 3.00 m

along a frictionless horizontal table by a constant applied force of magnitude

F = 18.0 N

directed at an angle

θ = 25.0°

below the horizontal as shown in the figure below.

A block labeled m is on a horizontal surface. An arrow labeled vector F points downward and to the right at an angle θ above the horizontal, and acts upon the upper left corner of the block. A faded image of the block is a distance d to the right of the block.

(a) Determine the work done by the applied force.

(b) Determine the work done by the normal force exerted by the table.

(c) Determine the work done by the force of gravity.

(d) Determine the work done by the net force on the block.

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Step 1 help_outlineImage TranscriptioncloseGfven Mass of the block, m2.50 kg Displacement, d = 3.00m Applred foce Fopphied Angle of foore Accelesatim due to pavty, g= 9.81 m/s2 250 F Horifantal frictionless Aurfae -d fullscreen
Step 2 help_outlineImage Transcriptionclosebee body dliagram of block FCos Fne (4) woxk done by appliedl foste. Wepp = Fapplnd)(d) coso - (l8.0 N) (3.00m) Coa C25.0) = 48.94 J fullscreen
Step 3 help_outlineImage TranscriptioncloseNoo mal foarie act on th loch fom the Auface N N-mg - Fsin=o Efy0 ma t FAino N = (2.50 19) ( 9.81 m/s)+ ({p.0N)Sin (25) 32.13 N fullscreen

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### Work,Power and Energy 