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Asked Dec 9, 2019
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A block of mass m is sliding on a frictionless table with a velocity of magnitude v, (Call this +x
direction). It splits into three pieces after an internal explosion: one with mass m, goes off in +x
direction with velocity of magnitude vị. A second piece, mass m,, goes off perpendicular to the original
direction, but still in the plane of the table, with velocity of magnitude v,. (Call this the +y direction).
Find the velocity of the third piece.
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A block of mass m is sliding on a frictionless table with a velocity of magnitude v, (Call this +x direction). It splits into three pieces after an internal explosion: one with mass m, goes off in +x direction with velocity of magnitude vị. A second piece, mass m,, goes off perpendicular to the original direction, but still in the plane of the table, with velocity of magnitude v,. (Call this the +y direction). Find the velocity of the third piece.

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Expert Answer

Step 1

conservation of momentum along +x direction is, 

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mv, %3D ти+(т-(т + m,))

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Step 2

conservation of momentum along y-direction

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0=m,v + (m-(m + m,)) và,

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Step 3

solve the above two equations to calculate the comp...

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ту, 3 ти+(т-(m +m.))v , — тъ - тч V3z (т-(т, +m)у htu - %aш Vay = т-(т, +т,)) Эх 0%3D ту +(m-(т+m))у, - (т- (т + т.) -т, у, ч, -т,у Vзу (т- (т, +т,)) Vзs

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Advanced Physics

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