Question

Asked Oct 9, 2019

A block of mass ?=353 gm=353 g is dragged with a string across a rough horizontal table. The string tension is ?=2.63 N,T=2.63 N, and it pulls upward at an angle of ?=44.0∘ϕ=44.0∘ with the horizontal. At one particular instant, the block is moving at a speed of ?=5.70 m/s.v=5.70 m/s. The coefficient of kinetic friction between the block and the table is ?k=0.699.

What is the power ?TPT supplied to the block by the string tension? What is the power ?fPf supplied by the force of friction?

Step 1

The expression for the power is given by,

Step 2

Here *P* denotes the power, *F* is the applied force and *v* is the velocity, *ϕ *is the angle between the direction of the Tension *T* and velocity *v* of the block.

From the above problem the tension *T* is supplying the necessary force for pulling the block of mass *m*.

Replace *T* in place of *F* in the above equation.

Substitute 5.70 m/s for the velocity *v* and 2.63 N for tension *T, *44**° **for *ϕ* and solve for the power *P*.

__ __Power supplied by the tension *T* to the above block is,

Step 3

b)

To calculate the power supplied by the force of friction, resolve the tension *T* into *x* and *y* components and f...

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