A block of mass 4.20 kg is pushed up against a wall by a force P that makes an angle of θ = 50.0° angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.300. (a) Determine the possible values for the magnitude of P that allow the block to remain stationary. (If there is no maximum, enter NONE in that answer blank.)|Pmax|=  N|Pmin|=  N

Question
Asked Oct 29, 2019
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A block of mass 4.20 kg is pushed up against a wall by a force P that makes an angle of θ = 50.0° angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.300.

 
(a) Determine the possible values for the magnitude of P that allow the block to remain stationary. (If there is no maximum, enter NONE in that answer blank.)
|Pmax|
=  N
|Pmin|
=  N
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Expert Answer

Step 1

(a)

The minimum force exerted on the block to avoid slide and the friction force will acts upwards.

Substitute the values,

P sin+Nmg
Р яiл 0+ пP_ соs0 - тg
Р- (sin @ + дсоsе)- тg
=
mg
sin@ + дсose
(4.20kg)(9.8m/s2)
sin50° +(0.300)cos(50°)
Р.
=42.9N
43N
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Image Transcriptionclose

P sin+Nmg Р яiл 0+ пP_ соs0 - тg Р- (sin @ + дсоsе)- тg = mg sin@ + дсose (4.20kg)(9.8m/s2) sin50° +(0.300)cos(50°) Р. =42.9N 43N

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Step 2

The maximum force exerted on the block to sliding upwards and the fr...

P.sn0- μΝ =m
P.sinθ-μP.. cs0- mg
P(nθ- μοs 0) = mg
πag
Р.
sin θ- μαs θ
(4.20ks) (9.3π/s")
Р.
sin50°-(0300)cos(50°)
-71.8N
72N
help_outline

Image Transcriptionclose

P.sn0- μΝ =m P.sinθ-μP.. cs0- mg P(nθ- μοs 0) = mg πag Р. sin θ- μαs θ (4.20ks) (9.3π/s") Р. sin50°-(0300)cos(50°) -71.8N 72N

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Newtons Laws of Motion

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