# A block with mass M = 5.75 kg is sliding in the positive x-direction at Vi = 8.40 m/s on a frictionless surface when it collides elastically in one dimension with a stationary block with mass m = 1.75 kg.Determine the velocities, Vf and vf, of the objects after the collision.Vf= m/svf= m/s

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A block with mass M = 5.75 kg is sliding in the positive x-direction at Vi = 8.40 m/s on a frictionless surface when it collides elastically in one dimension with a stationary block with mass m = 1.75 kg.

Determine the velocities,

Vf

and

vf,

of the objects after the collision.

 Vf = m/s vf = m/s
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Step 1

Consider the diagram given below for the given system. Here, vi is zero because the mass m is at rest initially.

Since the collision is elastic, the linear momentum of the system is conserved.

Thus, Step 2

For the elastic collision total kinetic energy of the system before and after the collision is conserved.

Thus, Substitute the value of vf in the above equation from equation (1). ...

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