A box placed on the three-piece-bar as shown in the figure. The bar is supported from points A and B. Part I and II of the bar has a mass of 0.25 kg, and the third part has a mass of 0.5 kg. (L=3 m) a) b) Draw the free body diagram. Find the reaction forces at points A and B. - 43 - 43 - L/3 * L/6 A B m,= m= 0.25 kg m= 0.5 kg maox = 2 kg

Principles of Physics: A Calculus-Based Text
5th Edition
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Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
Section: Chapter Questions
Problem 50P: A 5.00-kg block is placed on top of a 10.0-kg block (Fig. P5.50). A horizontal force of 45.0 N is...
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A box placed on the three-piece-bar as shown in the figure. The bar is
supported from points A and B. Part I and II of the bar has a mass of 0.25 kg, and the
third part has a mass of 0.5 kg. (L=3 m)
a)
b)
Draw the free body diagram.
Find the reaction forces at points A and B.
- 43 -- /3 -
L/3
* L/6+
%3D
A
m, = m= 0.25 kg
m- 0.5 kg
maox = 2 kg
Transcribed Image Text:A box placed on the three-piece-bar as shown in the figure. The bar is supported from points A and B. Part I and II of the bar has a mass of 0.25 kg, and the third part has a mass of 0.5 kg. (L=3 m) a) b) Draw the free body diagram. Find the reaction forces at points A and B. - 43 -- /3 - L/3 * L/6+ %3D A m, = m= 0.25 kg m- 0.5 kg maox = 2 kg
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