A boy throws a baseball onto a roof and it rolls back down andoff the roof with a speed of 3.75 m/s. If the roof is pitched at35.0° below the horizon and the roof edge is 2.50 m above theground, find (a) the time the baseball spends in the air, and(b) the horizontal distance from the roof edge to the pointwhere the baseball lands on the ground.

Question
Asked Dec 17, 2019
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A boy throws a baseball onto a roof and it rolls back down and
off the roof with a speed of 3.75 m/s. If the roof is pitched at
35.0° below the horizon and the roof edge is 2.50 m above the
ground, find (a) the time the baseball spends in the air, and
(b) the horizontal distance from the roof edge to the point
where the baseball lands on the ground.

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Expert Answer

Step 1

a)

The total time baseball spends in air can be determined using the equation of motion

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h = u,t+ Here histheheight,u, is the vertical component of velocity, gis the acceleration dueto gravity and tis the time h = u sin et + gt eis the angle

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Step 2

Then,

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2.5 m=(3.75m/s )sin 35°t +(9.8m/s )t 4.9t + 2.15t – 2.5 = 0 t= 0.527s

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Step 3

b)

Horizontal distance ...

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D = u,t Here u, isthehorizontal component of velocity D= u cos et

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