Question
Asked Sep 26, 2019

A brick is thrown upward from the top of a building at an angle of 15° to the horizontal and with an initial speed of 10 m/s. If the brick is in flight for 2.9 s, how tall is the building? (m)

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Step 1

The expression for the height of the building is,

1
2
1
y[vsin@|t+af
2
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1 2 1 y[vsin@|t+af 2

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Step 2

Substitute the ...

-[10)cin(15)](2.9)+(-9.8)(2.9)
=-33.70 m
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-[10)cin(15)](2.9)+(-9.8)(2.9) =-33.70 m

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Kinematics

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