Asked Nov 20, 2019

A brick is thrown upward from the top of a building at an angle of 30° to the horizontal and with an initial speed of 15 m/s. If the brick is in flight for 3.3 s, how tall is the building? 



Expert Answer

Step 1

Let the brick be projected at an angle θ from the horizontal from the top of the building.

Let the horizontal component of the launch velocity be denoted by vox and the vertical component of the launch velocity be denoted by voy

The two velocity components are represented as ,



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Vox =v cose = vsin e ох Voy

Step 2

Let the height of the building be denoted by h.

This height can be calculated in terms of the vertical motion of the brick.

Using the second kinematic equation, the height h can be computed as,

Also for the vertical motion of the brick


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Step 3

Use the above substitution in the secon...


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h=voy+ 2 1 (vsin0)t


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