A bullet (mass of 20 kg) is fired at a person wearing a bulletproof vest at 1500 m/s. The person is knocked back at 20 m/s but survives. The bullet just stops.a. What are the magnitude and direction of the impulse imparted by the person on the bullet?b. Calculate the force exerted by the person on the bullet (ignore gravity).

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Asked Nov 3, 2019
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A bullet (mass of 20 kg) is fired at a person wearing a bulletproof vest at 1500 m/s. The person is knocked back at 20 m/s but survives. The bullet just stops.

a. What are the magnitude and direction of the impulse imparted by the person on the bullet?

b. Calculate the force exerted by the person on the bullet (ignore gravity).

 
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Expert Answer

Step 1

(a) The magnitude and direction of the impulse...

(its given that mass ofthe bullet is 20 kg)
Let m be the mass of the person, then by applying conservation
of momentum, we get
Initial momentum =
Final momentum
(1500 x 20)+(mx o) =(20+ m)20
m =1480
or
Impulse imparted by the person on the bullet is the change in momentum
Thus, magnitude nv -mu,where v and u are the final and initial velocities
=480 x 20-0
29600 kg m/s
The directi on will be opposite to the direction of bullet
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(its given that mass ofthe bullet is 20 kg) Let m be the mass of the person, then by applying conservation of momentum, we get Initial momentum = Final momentum (1500 x 20)+(mx o) =(20+ m)20 m =1480 or Impulse imparted by the person on the bullet is the change in momentum Thus, magnitude nv -mu,where v and u are the final and initial velocities =480 x 20-0 29600 kg m/s The directi on will be opposite to the direction of bullet

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