Question

Asked Mar 28, 2019

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Step 1

Let *p* be the proportion of proportion of take-out orders.

The aim is to check whether the proportion of take-out orders is greater than 25%.

The null and the alternative hypothesis is,

Step 2

Here the level of significance is 0.05 and the *p*–value is 0.643.

*Decision based on the p–value method:*

- If
*p*≤ α, then reject.

*Conclusion:*

Here α = 0.05, *p*– value = 0.643.

Therefore, the *p*– value is not less than the significance level.

That is, 0.643 > 0.05.

Using the decision rule, fail to reject the null hypothesi...

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