A car accelerates from 0 to 60 mph (88 ft/sec) in 8.8 sec. The distance d(t) (in ft) that the car travels t seconds after motion begins is given by d(t) = 5t2, where 0sts 8.8. d(t + h) – d(t) a. Find the difference quotient. Use the difference quotient to determine the average rate of speed on the following intervals for t. b. [0, 2] c. [2, 4] d. [4, 6] e. [6, 8]

Question
A car accelerates from 0 to 60 mph (88 ft/sec) in 8.8 sec. The distance d(t) (in ft) that the car travels t seconds after motion
begins is given by d(t) = 5t2, where 0sts 8.8.
d(t + h) – d(t)
a. Find the difference quotient.
Use the difference quotient to determine the average rate of speed on the following intervals for t.
b. [0, 2]
c. [2, 4]
d. [4, 6]
e. [6, 8]
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Transcribed Image Text

A car accelerates from 0 to 60 mph (88 ft/sec) in 8.8 sec. The distance d(t) (in ft) that the car travels t seconds after motion begins is given by d(t) = 5t2, where 0sts 8.8. d(t + h) – d(t) a. Find the difference quotient. Use the difference quotient to determine the average rate of speed on the following intervals for t. b. [0, 2] c. [2, 4] d. [4, 6] e. [6, 8]