A car begins at the position x = 6.0.m with an initial velocity of 24.8 m/s. If the acceleration of the car is -2.80 m/s^2 find the position of the car after 2.70s in m. Just input the number in the answer box, don't input units. Also, note that the acceleration is negative here, so the car is slowing down.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
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A car begins at the position x = 6.0.m with an initial velocity of 24.8 m/s. If the acceleration of the car is -2.80 m/s^2 find the position of the car after 2.70s in m. Just input the number in the answer box, don't input units.

Also, note that the acceleration is negative here, so the car is slowing down.

Expert Solution
Step 1

Given data:

The initial position of the car is,

xi = 6.0.m

The initial velocity of the car is,

vi = 24.8 m/s

Acceleration of the car is,

a=  -2.80 m/s2

The time is,

t = 2.70 m

Formula used:

According to the Kinematical equation of motion, the final position of the object is,

xf= xi + vit + 12at2

Where,

xf - Final position of the object

xi - Initial position of the object

v - initial velocity of the object

a- Acceleration

t- Time

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