Question
Asked Oct 11, 2019
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A car can decelerate at -3.45 m/s2 without skidding when coming to rest on a level road.

What would its deceleration be if the road is inclined at 9.7 ∘ and the car moves uphill? Assume the same static friction coefficient.

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Expert Answer

Step 1

When the car decelerates on a level road, the deceleration force is provided by only the frictional force that acts on the car’s tires. That is,

F = f
(1)
Е MN
та
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F = f (1) Е MN та

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Step 2

Here, a is the car’s deceleration value, N is the normal force that acts on the car’s tires and µ is the friction’s coefficient.

Since on a level road the normal force on the car is balanced by its weight, we have,

N mg
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N mg

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Step 3

Substitute mg for N in equation (1) and so...

)
та 3D и(mg
а
и-
g
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) та 3D и(mg а и- g

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Tagged in

Science

Physics

Friction

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