Question
Asked Sep 12, 2019
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A car is moving at a velocity of 20 m/s. The car then accelerates uniformly at 1.8 m/s2. The car continues at the same acceleration until it reaches a velocity of 25 m/s, which is the legal speed limit. What is the distance the car travels in while accelerating?

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Expert Answer

Step 1

Given information:

Initial velocity of the car (u) = 20 m/s.

Final velocity of the car (v) = 25 m/s.

Acceleration of the car (a) = 1.8 m/s2

Step 2

From the definition of average acceleration (a), we can relate these quantities as:

25-20
v-u
1
t
t
Where "t is the time taken to reach from initial velocity to final velocity
we can get the value of "t" from the above equation as:
t 2.77 s
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Image Transcriptionclose

25-20 v-u 1 t t Where "t is the time taken to reach from initial velocity to final velocity we can get the value of "t" from the above equation as: t 2.77 s

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Step 3

From the 2nd equation of motion we find the distance (s) travelled by t...

ut
it2
Substitute the corresponding value in the equation we get:
s 55.4 6.90 62.30 m
help_outline

Image Transcriptionclose

ut it2 Substitute the corresponding value in the equation we get: s 55.4 6.90 62.30 m

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Science

Physics

Kinematics

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