Question
Asked Nov 10, 2019
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A car moving at 9.5 m/s crashes into a tree and stops in 0.32 s.

Part (a)  Calculate the magnitude of the force, in newtons, the seatbelt exerts on a passenger in the car to bring him to a halt. The mass of the passenger is 71 kg.

Part (b)  What would the final velocity be, in meters per second, if the car with the 71-kg passenger had collided with (and stuck to) a car that has a mass equal to and is traveling in the opposite direction and at the same speed?

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Expert Answer

Step 1

(a) Using the kinematic equation of motion,

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1 (v+u) 2 1 (9.5m/s)(0.32s) 2 1.52m

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Step 2

By using equation of motion to solve for acceleration,

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at 2 [21 2 (ut-s) [3] 2 (9.5m/s)(0.32 s)-(1.52m) (0.32 s) -29.69m/s2

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Step 3

The magnitude of...

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F =ma [41 (71kg)(29.69m/s) = 2107.99 N

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Tagged in
SciencePhysics

Kinematics

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