A car of mass 922 kg is traveling 23.9 m/s when the driver applies the brakes, which lock the wheels. The car skids for 4.27 s in the positive x-direction before coming to rest. (a)What is the car's acceleration (in m/s2)? (Indicate the direction with the sign of your answer.) .  (b)What magnitude force (in N) acted on the car during this time?  (c)How far (in m) did the car travel?

Question
Asked Nov 16, 2019
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A car of mass 922 kg is traveling 23.9 m/s when the driver applies the brakes, which lock the wheels. The car skids for 4.27 s in the positive x-direction before coming to rest.
 
(a)
What is the car's acceleration (in m/s2)? (Indicate the direction with the sign of your answer.) . 
 
(b)
What magnitude force (in N) acted on the car during this time?
 
 
(c)
How far (in m) did the car travel?
 
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Expert Answer

Step 1
Given that
mass of the car m 922 kg
initial velocity v, = 23.9m/s
final velocity v, = Om/s
4.27 s
Time t
Acceleration is given by
1
t
Om/s 23.9m/s
4.27 s
-5.597m/s2
(a)The acceleration of the car is -5.597m/s2
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Given that mass of the car m 922 kg initial velocity v, = 23.9m/s final velocity v, = Om/s 4.27 s Time t Acceleration is given by 1 t Om/s 23.9m/s 4.27 s -5.597m/s2 (a)The acceleration of the car is -5.597m/s2

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Step 2

Write the expression...

F
= ma
considering the magnitude of the
(922kg) (5.597m/s)
acceleration alone
= 5160.60 N
(b)magnitude of force acted on the car is 5160.60 N
help_outline

Image Transcriptionclose

F = ma considering the magnitude of the (922kg) (5.597m/s) acceleration alone = 5160.60 N (b)magnitude of force acted on the car is 5160.60 N

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