Question
Asked Oct 5, 2019
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A certain rain cloud at an altitude of 2.10 km contains 3.20 x 10 kq of water vapor. How long would it take for a 2.95-kW
pump to raise the amount of water from Earth's surface to the cloud's position?
h
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A certain rain cloud at an altitude of 2.10 km contains 3.20 x 10 kq of water vapor. How long would it take for a 2.95-kW pump to raise the amount of water from Earth's surface to the cloud's position? h

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Step 1

Given values:

Mass of the water vapor, m = 3.20 x 107 kg

Height of water be raises, H = 2.10 km = 2.10 x 103 m

Power of the pump, P = 2.95 Kw =2.95 x 103 W

Let the time taken to raise the water from the  earth\'s surface be t

Step 2

The energy required to raise the water to the altitude H:

U = mgH
3.20x 10 x9.8x 2.10 x103
= 65.85 x1010 jouls
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U = mgH 3.20x 10 x9.8x 2.10 x103 = 65.85 x1010 jouls

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Step 3

Writing the formul...

Energy
P =
Time
U
t
Plugging in the given values:
2.95x10265.85 x 1010
t
t 22.32x10
t =2.23x108 s
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Energy P = Time U t Plugging in the given values: 2.95x10265.85 x 1010 t t 22.32x10 t =2.23x108 s

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