A charge of -3.50 µC is placed at a point that is 1.00 cm to the right of the 1.50 µC charge shown in the figure. What are the magnitude and direction of the electric (Coulomb) force on the -3.50 µC charge? 6.00 µC 1.50 µC -2.00 μC 3.00 cm + 2.00 cm O 524 N towards the right 1,220 N towards the left O 2,070 N towards the right O 2,170 N towards the left 1,390 N towards the right

A charge of -3.50 µC is placed at a point that is 1.00 cm to the right of the 1.50 µC charge shown in the figure. What are the magnitude and direction of the electric (Coulomb) force on the -3.50 µC charge? 6.00 µC 1.50 µC -2.00 μC 3.00 cm + 2.00 cm O 524 N towards the right 1,220 N towards the left O 2,070 N towards the right O 2,170 N towards the left 1,390 N towards the right

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 23P: A rod 14.0 cm long is uniformly charged and has a total charge of 22.0 C. Determine (a) the...

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A rod 14.0 cm long is uniformly charged and has a total charge of 22.0 C. Determine (a) the magnitude and (b) the direction of the electric field along the axis of the rod at a point 36.0 cm from its center.
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
A point charge of 4.00 nC is located at (0, 1.00) m. What is the x component of the electric field due to the point charge at (4.00, 2.00) m? (a) 1.15 N/C (b) 0.864 N/C (c) 1.44 N/C (d) 1.15 N/C (e) 0.864 N/C
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
Three charged particles are located at the corners of an equilateral triangle as shown in Figure P19.9. Calculate the total electric force on the 7.00-C charge.
(a) Find the total Coulomb force on a charge of 2.00 nC located at x = 4.00 cm in Figure 18.52 (b): given that q = 1,00C . (b) Find the x-position at which the electric field is zero in Figure 18.52 (b).
A 1.75-nC charged particle located at the origin is separated by a distance of 0.0825 m from a 2.88-nC charged particle located farther along the positive x axis. Both particles are held at their locations by an external agent. a. What is the electrostatic force on the 2.88-nC particle? b. What is the electrostatic force on the 1.75-nC particle?
An infinite line of positive charge lies along the y axis, with charge density = 2.00 C/m. A dipole is placed with its center along the x axis at x = 25.0 cm. The dipole consists of two charges 10.0 C separated by 2.00 cm. The axis of the dipole makes an angle of 35.0 with the x axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole.
A very small ball has a mass of 5.00 103 kg and a charge of 4.00 C. What magnitude electric field directed upward will balance the weight of the ball so that the ball is suspended motionless above the ground? (a) 8.21 102 N/C (b) 1.22 104 N/C (c) 2.00 102 N/C (d) 5.11 106 N/C (e) 3.72 103 N/C
A 1.75-nC charged particle located at the origin is separated by a distance of 0.0825 m from a 2.88-nC charged particle located farther along the positive x axis. If the 1.75-nC particle is kept fixed at the origin, where along the positive x axis should the 2.88-nC particle be located so that the magnitude of the electrostatic force it experiences is twice as great as it was in Problem 27?
Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric force on the other with magnitude FE. a. In terms of these quantities, what separation distance would cause the magnitude of the electric force to be halved? b. In terms of these quantities, what separation distance would cause the magnitude of the electric force to be doubled?
Two point charges attract each other with an electric force of magnitude F. If the charge on one of the particles is reduced to one-third its original value and the distance between the particles is doubled, what is the resulting magnitude of the electric force between them? (a) 112F (b) 13F (c) 16F (d) 34F (e) 32F