A chemical company makes two brands of antifreeze. The first brand is 70% pure antifreeze, and the second brand is 95% pureantifreeze. In order to obtain 160 gallons of a mixture that contains 80% pure antifreeze, how many gallons of each brand of antifreezemust be used?Note that the ALEKS graphing calculator can be used to make computations easier.I gallonsFirst brand:Second brand:gallons

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Asked Dec 19, 2019
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A chemical company makes two brands of antifreeze. The first brand is 70% pure antifreeze, and the second brand is 95% pure
antifreeze. In order to obtain 160 gallons of a mixture that contains 80% pure antifreeze, how many gallons of each brand of antifreeze
must be used?
Note that the ALEKS graphing calculator can be used to make computations easier.
I gallons
First brand:
Second brand:
gallons
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A chemical company makes two brands of antifreeze. The first brand is 70% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 160 gallons of a mixture that contains 80% pure antifreeze, how many gallons of each brand of antifreeze must be used? Note that the ALEKS graphing calculator can be used to make computations easier. I gallons First brand: Second brand: gallons

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Expert Answer

Step 1
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Let the two brands be x and y Given first brand x makes 70% of antifreeze Second brand y makes 95% of antifreezel Obtain 160 gallons of mixture that contains 80% of antifreeze

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Step 2
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Total number of gallons = 160 -(i) x+y=160 75%of x +95%ofy = 80%of (x + y) = 75x +95y = 80(x+y) =75x+95y =80x +80y = 75x +95y – 80x – 80y = 80x + 80y – 80x – 80y =-5x +15 y = 0 = 5x =15y 15y =x = - 5 =x = 3y

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