A chemist has three different acid solutions. The first acid solution contains 20%20% acid, the second contains 30%30% and the third contains 50%50%. He wants to use all three solutions to obtain a mixture of 8585liters containing 40%40% acid, using 33 times as much of the 50%50% solution as the 30%30% solution. How many liters of each solution should be used?
A chemist has three different acid solutions. The first acid solution contains 20%20% acid, the second contains 30%30% and the third contains 50%50%. He wants to use all three solutions to obtain a mixture of 8585liters containing 40%40% acid, using 33 times as much of the 50%50% solution as the 30%30% solution. How many liters of each solution should be used?
Chapter4: Systems Of Linear Equations
Section4.3: Solve Mixture Applications With Systems Of Equations
Problem 4.53TI: Translate to a system of equations and solve: LeBron needs 150 milliliters of a 30% solution of...
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A chemist has three different acid solutions. The first acid solution contains 20%20% acid, the second contains 30%30% and the third contains 50%50%. He wants to use all three solutions to obtain a mixture of 8585liters containing 40%40% acid, using 33 times as much of the 50%50% solution as the 30%30% solution. How many liters of each solution should be used?
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