Question
Asked Oct 12, 2019
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A chemist has two alloys, one of which is 5% gold and 15% lead and the other which is 40% gold and 30% lead. How many grams of each of the two alloys should be used to make an alloy that contains 39 g of gold and 81 g of lead?

first alloy     g
second alloy     g
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Expert Answer

Step 1

A chemist has two alloys, one of which is 5% gold and 15% lead and the other which is 40% gold and 30% lead. The grams of each of the two alloys that should be used to make an alloy that contains 39 g of gold and 81 g of lead are to be calculated.

Step 2

Let x be the total amount of Alloy 1 and y be the total amount of alloy 2 that should be used to make an alloy that contains 39 g of gold and 81 g of lead .

Now, Alloy 1 has 5% gold and 15% lead.

And alloy 2 has 40% gold and 30% lead.

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Total mass of gold 5% of x + 40% of y and Total mass of lead = 15% of x + 30% of y

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Step 3

Now,

The mass of gold in new alloy = 39 g

And the...

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39 g 5% of x + 40% of y equation and 81 g 15% of x 30% of y equation 2

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