Question

Asked Oct 24, 2019

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A chemist makes (730.mL) of sodium carbonate (Na_{2}CO_{3}) working solution by adding distilled water to 200. mL of a 0.287 M stock solution of sodium carbonate in water. Calculate the concentration of the chemist's working solution. Be sure your answer has the correct number of significant digits.

Step 1

The molarity of a solution is defined as the number of moles of solute present in one-liter solution, as stated in equation (1); M is the molarity of solution, n is the number of moles, and V is the volume of solution in liters.

Step 2

The conversion factor for mL and L units is,

1 mL = 10^{-3} L

Hence, the volume 200 mL is equal to 0.200 L and the volume 730 mL is equal to 0.730 L.

The number of moles of sodium carbonate in the primary solution is calculated using equation (1),

Step 3

The concentration of the final sodium carbonate s...

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