A chemist makes (730.mL) of sodium carbonate (Na2CO3) working solution by adding distilled water to 200. mL of a 0.287 M stock solution of sodium carbonate in water. Calculate the concentration of the chemist's working solution. Be sure your answer has the correct number of significant digits.

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Asked Oct 24, 2019
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A chemist makes (730.mL) of sodium carbonate (Na2CO3) working solution by adding distilled water to 200. mL of a 0.287 M stock solution of sodium carbonate in water. Calculate the concentration of the chemist's working solution. Be sure your answer has the correct number of significant digits.

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Expert Answer

Step 1

The molarity of a solution is defined as the number of moles of solute present in one-liter solution, as stated in equation (1); M is the molarity of solution, n is the number of moles, and V is the volume of solution in liters.

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(1) м V(in L)

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Step 2

The conversion factor for mL and L units is,

1 mL = 10-3 L

Hence, the volume 200 mL is equal to 0.200 L and the volume 730 mL is equal to 0.730 L.

The number of moles of sodium carbonate in the primary solution is calculated using equation (1),

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0.287 mol/L 0.200 L n 0.0574 mol

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Step 3

The concentration of the final sodium carbonate s...

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0.0574 mol 0.730 L 0.0786 M

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