Question

A chromium containing compound has a formula Fe_{x}Cr_{y}O_{4} and is 28.59% oxygen by mass

Find x and y

Step 1

Given, mass percentage of O in FexCryO4 = 28.59%

Molar mass of 4 O in FexCryO4 = 4 × 16 g/mol = 64 g/mol

Mass percentage is expressed as:

Step 2

The molar mass of Fe_{x}Cr_{y}O_{4} can be expressed as:

Step 3

So, the sum of [x(55.85 g/mol) + y(52 g/mol)] must not exceed 159.85 g/mol. And there must be at least one Fe and one Cr in FexCryO4. Now, from equation (1) we ...

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