A circuit is connected to a battery that contains an internal resistance. As power is dissipated through the circuit, its temperature increases, causing the resistance of the circuit connected to the battery to increase. Assuming that the internal resistance of the battery does not change, how does this affect (decrease, increase, or remain the same) the terminal voltage of the battery? Be sure to explain your reasoning.

A circuit is connected to a battery that contains an internal resistance. As power is dissipated through the circuit, its temperature increases, causing the resistance of the circuit connected to the battery to increase. Assuming that the internal resistance of the battery does not change, how does this affect (decrease, increase, or remain the same) the terminal voltage of the battery? Be sure to explain your reasoning.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter29: Direct Current (dc) Circuits

Section: Chapter Questions

Problem 51PQ

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