Question
Asked Jan 30, 2020
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A circular rod has a radius of curvature R = 9.01 cm and a uniformly distributed charge Q = 6.62 pC and it subtends an angle θ = 2.40 rad. What is the magnitude of the electric field that Q produces at the center of curvature?
_________N/C

(please include units so that I can follow the steps easier)

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Expert Answer

Step 1

Let assume two small elements dq from the rod one from each half of the rod. At centre of curvature O, the sine compoennts of the fields will get cancelled and only cos components will remai...

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Electric Charges and Fields

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