A conservationist suspects that the water level in Horseshoe Lake has been affected more by the current drought than the water level in Swan Lake, so he measures how far the water level is below normal each day in June. The data ar normally distributed. Compute the test value and test his hypothesis at a= 0.01 Hor seshoe Lake Swan Lake X = 43.0 cm X2 = 38.6 cm = 3.2 cm o =24 cm "1= 30 2= 30

A conservationist suspects that the water level in Horseshoe Lake has been affected more by the current drought than the water level in Swan Lake, so he measures how far the water level is below normal each day in June. The data ar normally distributed. Compute the test value and test his hypothesis at a= 0.01 Hor seshoe Lake Swan Lake X = 43.0 cm X2 = 38.6 cm = 3.2 cm o =24 cm "1= 30 2= 30

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.1: Measures Of Center

Problem 9PPS

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