A cord passing over a pulley connects two masses, as shown, where m₁ = 3.60 kg and m₂ = 6.90 kg. Assume the pulley and surfaces are frictionless, and the cord is massless and does not stretch. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) m₁ 35.0⁰ m₂ 35.0°/ (a) What is the acceleration of each block? (Enter the magnitude in m/s².) m/s² (b) What is the tension in the cord (in N)? N

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 33P: Two blocks, each of mass m = 3.50 kg, are hung from the ceiling of an elevator as in Figure P4.33....
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A cord passing over a pulley connects two masses, as shown, where m₁ = 3.60 kg and m₂ = 6.90 kg. Assume the pulley and
surfaces are frictionless, and the cord is massless and does not stretch. (Due to the nature of this problem, do not use rounded
intermediate values in your calculations-including answers submitted in WebAssign.)
m,
35.0°
35.0°
m₂
(a) What is the acceleration of each block? (Enter the magnitude in m/s².)
m/s²
(b) What is the tension in the cord (in N)?
N
Transcribed Image Text:A cord passing over a pulley connects two masses, as shown, where m₁ = 3.60 kg and m₂ = 6.90 kg. Assume the pulley and surfaces are frictionless, and the cord is massless and does not stretch. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) m, 35.0° 35.0° m₂ (a) What is the acceleration of each block? (Enter the magnitude in m/s².) m/s² (b) What is the tension in the cord (in N)? N
Expert Solution
Step 1

Given:-

The mass  of the block is m1= 3.60 kg and m2=6.90 kg 

The pulley is frictionless and the cord is massless 

The angle at which blocks are on show in the figure is θ=35°

Find:- 

a) The acceleration of each block?

b) The tension in the cord?

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