Question
Asked Oct 14, 2019
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A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 24.0 m/s. A net is positioned a horizontal distance of 49.5 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil? 

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Expert Answer

Step 1

Given

Angle of shot out a canon = 45

Initial speed of the canon (u) = 26.5 m/s

Horizontal position of the net (R) = 49.5 m/s

Step 2

Calculating the vertical position

Equation ...

1 gx
2 u cos2e
9.8(49.5)
2 (26.5) cos (45)
yxtan
1
y=49.5tan 45
19.8x2450.25
y 49.5x1
2
702.25x
2
y=49.5-34.2
y15.3 m
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1 gx 2 u cos2e 9.8(49.5) 2 (26.5) cos (45) yxtan 1 y=49.5tan 45 19.8x2450.25 y 49.5x1 2 702.25x 2 y=49.5-34.2 y15.3 m

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Physics

Kinematics

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