Asked Dec 4, 2019

A dockworker pushes a 50 kg crate with a downward force of 300 Newton's, at an angle of 30 degrees with the horizontal. The coefficient of kinetic friction is 0.30.

a. What is the normal force?

b. WHat is the inetic friction once the crate starts moving?

c. What is the acceleration of the crate?


Expert Answer

Step 1

(a) write the expression for net vertical force


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EF, = N– mg – F sin 0 = 0 N = mg +F sin e

Step 2

Substitute the values


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N= (50kg) (9.8 m/s")+(300 N) sin (30°) = 640 N

Step 3

(b) Write the expression for k...


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