A du 21. t = -/4beues 24. t = -11#/6eo U 22. t = -7/425. t = -5T/323. t %3D -5п/626. t3D -2п/3%3DIn Problems 27-32, find the given trigonometric function value. Do not use acalculator.tionsC0E0.8Te27. sin(-117/3)28. cos(17T/6)31. cos 5729. cos(-7/4)32. sin(23/3)30, sin(-197/2)In Problems 33–38, justify the given statement with one of the properties of thetrigonometric functions.nen33. sin T =sin 3735. sin(-3 – T) = –sin(3 + )a37. cos 0.43 = cos(-0.43)34. cos(T/4) = sin(/4)= cos 14.87T38. sin(27/3) = sin(7/3)36. сos 16.87п%3D%3D%3DIn Problems 39–46, find the given trigonometric function value. Do not use acalculator.istq40. cos 150°42. sin270°44. sin(-180°)46. cos(-300°)39. sin o41. cos 210°lg bonsg faiwaibousg43. cos 330°45. sin(-60°)In Problems 47-50, firall angles t, where 0

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Asked Mar 19, 2020
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How do I do #32?

A du 21. t = -/4
beues 24. t = -11#/6
eo U 22. t = -7/4
25. t = -5T/3
23. t %3D -5п/6
26. t3D -2п/3
%3D
In Problems 27-32, find the given trigonometric function value. Do not use a
calculator.
tions
C0E0.8Te
27. sin(-117/3)
28. cos(17T/6)
31. cos 57
29. cos(-7/4)
32. sin(23/3)
30, sin(-197/2)
In Problems 33–38, justify the given statement with one of the properties of the
trigonometric functions.
nen
33. sin T =
sin 37
35. sin(-3 – T) = –sin(3 + )
a37. cos 0.43 = cos(-0.43)
34. cos(T/4) = sin(/4)
= cos 14.87T
38. sin(27/3) = sin(7/3)
36. сos 16.87п
%3D
%3D
%3D
In Problems 39–46, find the given trigonometric function value. Do not use a
calculator.
istq
40. cos 150°
42. sin270°
44. sin(-180°)
46. cos(-300°)
39. sin o
41. cos 210°
lg bonsg faiwaibousg
43. cos 330°
45. sin(-60°)
In Problems 47-50, firall angles t, where 0 <t << 2, that satisfy the given condition.
47. sint = 0
49. cost = V2
48. cost = -1
50, sint = ;
%3D
beycl
In Problems 5
find all angles 0, where 0° < 0 < 360°, that satisfy the given
condition.
52. sin0 = -
/2
V2/2
S51. cos0
%3D
53. sine
54. cos 0 = 1
to
0 App
do sW.n.01 Iavroini or no
ons ioq2ug
Throw Under certain conditions the maximum height y attained by a bas-
55
ball released from a height h at an angle 0 measured from the horizontal with
Rinitial velocity vọ is given by y = h + (výsin-0)/2g, where g is the accelera-
ion due to gravity. Compute the maximum height reached by a free throw if
%3D
1 479 ond
O 81 m/2
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A du 21. t = -/4 beues 24. t = -11#/6 eo U 22. t = -7/4 25. t = -5T/3 23. t %3D -5п/6 26. t3D -2п/3 %3D In Problems 27-32, find the given trigonometric function value. Do not use a calculator. tions C0E0.8Te 27. sin(-117/3) 28. cos(17T/6) 31. cos 57 29. cos(-7/4) 32. sin(23/3) 30, sin(-197/2) In Problems 33–38, justify the given statement with one of the properties of the trigonometric functions. nen 33. sin T = sin 37 35. sin(-3 – T) = –sin(3 + ) a37. cos 0.43 = cos(-0.43) 34. cos(T/4) = sin(/4) = cos 14.87T 38. sin(27/3) = sin(7/3) 36. сos 16.87п %3D %3D %3D In Problems 39–46, find the given trigonometric function value. Do not use a calculator. istq 40. cos 150° 42. sin270° 44. sin(-180°) 46. cos(-300°) 39. sin o 41. cos 210° lg bonsg faiwaibousg 43. cos 330° 45. sin(-60°) In Problems 47-50, firall angles t, where 0 <t << 2, that satisfy the given condition. 47. sint = 0 49. cost = V2 48. cost = -1 50, sint = ; %3D beycl In Problems 5 find all angles 0, where 0° < 0 < 360°, that satisfy the given condition. 52. sin0 = - /2 V2/2 S51. cos0 %3D 53. sine 54. cos 0 = 1 to 0 App do sW.n.01 Iavroini or no ons ioq2ug Throw Under certain conditions the maximum height y attained by a bas- 55 ball released from a height h at an angle 0 measured from the horizontal with Rinitial velocity vọ is given by y = h + (výsin-0)/2g, where g is the accelera- ion due to gravity. Compute the maximum height reached by a free throw if %3D 1 479 ond O 81 m/2

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