A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by anadult is 5 minutes. He decides to collect data to see if the mean amount of time that college students spend in the showeris significantly different from 5 minutes. In a sample of 15 students, he found the average time was 4.61 minutes and thestandard deviation was 0.75 minutes. Using this sample information, conduct the appropriate hypothesis test at the 0.05level of significance. Assume normality.a) What are the appropriate null and alternative hypotheses?Но: х= 5 versus Ha: x # 55 versus Ha: H< 5Но: и5 versus Ha: l > 5Но: иНо: и5 versus Ha: l # 5b) What is the test statistic? Give your answer to four decimal places. -2.0140c) What is the P-value for the test? Give your answer to four decimal places. 1.9560Xd) What is the appropriate conclusion?Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05Fail to reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.05.Reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.05Reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05

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Asked Oct 30, 2019
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A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an
adult is 5 minutes. He decides to collect data to see if the mean amount of time that college students spend in the shower
is significantly different from 5 minutes. In a sample of 15 students, he found the average time was 4.61 minutes and the
standard deviation was 0.75 minutes. Using this sample information, conduct the appropriate hypothesis test at the 0.05
level of significance. Assume normality.
a) What are the appropriate null and alternative hypotheses?
Но: х
= 5 versus Ha: x # 5
5 versus Ha: H< 5
Но: и
5 versus Ha: l > 5
Но: и
Но: и
5 versus Ha: l # 5
b) What is the test statistic? Give your answer to four decimal places. -2.0140
c) What is the P-value for the test? Give your answer to four decimal places. 1.9560
X
d) What is the appropriate conclusion?
Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05
Fail to reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.05.
Reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.05
Reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05
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A facilities manager at a university reads in a research report that the mean amount of time spent in the shower by an adult is 5 minutes. He decides to collect data to see if the mean amount of time that college students spend in the shower is significantly different from 5 minutes. In a sample of 15 students, he found the average time was 4.61 minutes and the standard deviation was 0.75 minutes. Using this sample information, conduct the appropriate hypothesis test at the 0.05 level of significance. Assume normality. a) What are the appropriate null and alternative hypotheses? Но: х = 5 versus Ha: x # 5 5 versus Ha: H< 5 Но: и 5 versus Ha: l > 5 Но: и Но: и 5 versus Ha: l # 5 b) What is the test statistic? Give your answer to four decimal places. -2.0140 c) What is the P-value for the test? Give your answer to four decimal places. 1.9560 X d) What is the appropriate conclusion? Fail to reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05 Fail to reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.05. Reject the claim that the mean time is 5 minutes because the P-value is smaller than 0.05 Reject the claim that the mean time is 5 minutes because the P-value is larger than 0.05

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Expert Answer

Step 1

Since, we only answer up to 3 sub-parts, we'll answer the first 3. Please resumbit the question and specify the other sub part you'd like answered.

Step 2

The provided information are:

Hypothesized mean (µo) = 5

Sample size (n) = 15

Sample mean (x̄) = 4.61

Sample standard deviation (s) = 0.75

Step 3

(a)

The null and alternative...

H, 5
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H, 5

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