A farmer picks pumpkins from a large field. The farmer makes samples of 260 pumpkins and inspects them. If one infifty pumpkins are not fit to market and will be saved for seeds, what is the standard deviation of the mean of the samplingdistribution of sample proportions?

Question
Asked Oct 22, 2019

A farmer picks pumpkins from a large field. The farmer makes samples of 260 pumpkins and inspects them. If one in
fifty pumpkins are not fit to market and will be saved for seeds, what is the standard deviation of the mean of the sampling
distribution of sample proportions?

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Expert Answer

Step 1

Solution:

From the given information, the sample of pumpkins is 260, in one in

50 pumpkins are not fit to market.

The proportion value is,

х
р
1
50
0.02
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х р 1 50 0.02

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Step 2

The mean of sampling distribution of sample proportion is obtained below:

-260 x0.02
-52
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-260 x0.02 -52

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Step 3

The standard deviation of the mean of the sampling distribution of sample prop...

gmp(1-p)
260 (0.02 ) (1 -0.02)
= 2.25 74
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gmp(1-p) 260 (0.02 ) (1 -0.02) = 2.25 74

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