A firefighting crew uses a water cannon that shoots water at 27.0 m/s at a fixed angle of 50.0 ∘ above the horizontal. The firefighters want to direct the water at a blaze that is 12.0 m above ground level. How far from the building should they position their cannon? There are two possibilities (d1<d2); can you get them both? (Hint: Start with a sketch showing the trajectory of the water.)Part A:d1=_____mPart B:d2=______m

Question
Asked Sep 2, 2019

A firefighting crew uses a water cannon that shoots water at 27.0 m/s at a fixed angle of 50.0 ∘ above the horizontal. The firefighters want to direct the water at a blaze that is 12.0 m above ground level. How far from the building should they position their cannon? There are two possibilities (d1<d2); can you get them both? (Hint: Start with a sketch showing the trajectory of the water.)

Part A:

d1=_____m

Part B:

d2=______m 

check_circleExpert Solution
Step 1

Draw the trajectory of motion of water.

h12 m
h12 m
50
-d
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h12 m h12 m 50 -d

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Step 2

Write the expression of initial horizontal and vertical component of velocity for water cannon.

= vcos 50
V, = vsin 50°
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= vcos 50 V, = vsin 50°

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Step 3

Write the kinematic equation for ...

1
h=vt
gr
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1 h=vt gr

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