Question

Asked Oct 15, 2019

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A fixed amount of a particular ideal gas at 168C and a pressure of 1.75 3 105 Pa occupies a volume of 2.75 m3. If the volume is increased to 4.20 m3 and the temperature is raised to 26.48C, what will be the new pressure of the gas?

Step 1

Given values:

Initial pressure, P_{1} = 1.75 x 10^{5} Pa

Final pressure, P_{2} =?

T_{1} = 16.8 ^{o}C = 16.8 + 273 = 289.8 K

T_{2 }= 26.48 ^{o}C = 299.48 K

V_{1} = 2.75 m^{3}

V_{2} = 4.20 m^{3 }

Step 2

The ideal gas equation:

Step 3

From the ideal gas...

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