A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use 4, - Hz, where 4, is Team B and u, is Team A.) O Ho: Hy = Hz Ho: H = = 0.5 H1: H, = 0.5 O Ho: Hq = Hz O Hoi Hq> Hz B (b) What is the mean difference in weight (in pounds) between the two teams? (Use 4 - 42, where 4, is Team B and u, is Team A.) Ibs Which team, on average, had the higher weight? O Team A Team B O not enough information B (c) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 99% confidence level. (Round your answers to three decimal places.) t-statistic critical value p-value B (d) At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks. The null hypothesis should -Select- . The mean weights between the two teams --Select-- V significantly different at the 99%% confidence level.

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Topic Video
Question
Oneway Analysis of Weight By Team
Oneway Analysis of Weight By Team
350
Pooled t Test
Summary of Fit
300
Rsquare
0.000754
Adj Rsquare
Root Mean Square Error
Mean of Response
-0.03493
40.18232
250-
254.8887
Observations (or Sum Wgts)
30
t Test
200-
B-A
Assuming equal variances
Difference
2.133 t Ratio
14.673
42.677 Prob > IE|
0.145397
Тeam
Std Err Dif
DF
28
Upper CL Dif
0.8854
Lower CL Dif -38.411 Prob >t
0.4427
Pooled t Test
Confidence
0.99 Prob < t
0.5573
Summary of Fit
Analysis of Variance
Rsquare
0.000754
Adj Rsquare
Root Mean Square Error
Mean of Response
Source DF Sum of Squares Mean Square
Тeam
-0.03493
40.18232
1
34.133
34.13
254.8887
Error
28
45209.333
1614.62
Observations (or Sum Wgts)
30
C. Total
29
45243.467
t Test
Means for Oneway Anova
В-А
Level Number
Mean Std Error Lower {
A
15 253.800
10.375
22
Assuming equal variances
2.133 t Ratio
14.673 DF
32.189 Prob > |t|
Difference
0.145307
15 255.933
10.375
227
Std Err Dif
28
Std Error uses a pooled estimate of error variano
Upper CL Dif
0.8854
Lower CL Dif -27.922 Prob >t
0.4427
t Test
Confidence
0.95 Prob <t
0.5573
-40 -20 0 20
B-A
Assuming unequal variances
2.133 t Ratio
14.673 DF
42.677 Prob > ||
Difference
0.145397
Analysis of Variance
Std Err Dif
27.99884
Upper CL Dif
Lower CL Dif -38.411
Confidence
0.8854
Source DF Sum of Squares Mean Square FRatio Prob >F
Prob >t
0.4427
Тeam
1
34.133
34.13
0.0211
0.8854
0.99 Prob <t
0.5573
Error
28
45209.333
1614.62
C. Total 29
45243.467
Means for Oneway Anova
Level Number
Mean
Std Error Lower 95% Upper 95%
A
15 253.800
10.375
232.55
275.05
15 255.933
10.375
234.68
277.19
Std Error uses a pooled estimate of error variance
t Test
В-А
Assuming unequal variances
2.133 t Ratio
14.673 DF
32.189 Prob > |t|
Difference
0.145397
Std Err Dif
27.99884
Upper CL Dif
0.8854
Lower CL Dif -27.922 Prob >t
0.4427
Confidence
0.95 Prob <t
0.5573
-40
-20
20
40
Weight
II
Transcribed Image Text:Oneway Analysis of Weight By Team Oneway Analysis of Weight By Team 350 Pooled t Test Summary of Fit 300 Rsquare 0.000754 Adj Rsquare Root Mean Square Error Mean of Response -0.03493 40.18232 250- 254.8887 Observations (or Sum Wgts) 30 t Test 200- B-A Assuming equal variances Difference 2.133 t Ratio 14.673 42.677 Prob > IE| 0.145397 Тeam Std Err Dif DF 28 Upper CL Dif 0.8854 Lower CL Dif -38.411 Prob >t 0.4427 Pooled t Test Confidence 0.99 Prob < t 0.5573 Summary of Fit Analysis of Variance Rsquare 0.000754 Adj Rsquare Root Mean Square Error Mean of Response Source DF Sum of Squares Mean Square Тeam -0.03493 40.18232 1 34.133 34.13 254.8887 Error 28 45209.333 1614.62 Observations (or Sum Wgts) 30 C. Total 29 45243.467 t Test Means for Oneway Anova В-А Level Number Mean Std Error Lower { A 15 253.800 10.375 22 Assuming equal variances 2.133 t Ratio 14.673 DF 32.189 Prob > |t| Difference 0.145307 15 255.933 10.375 227 Std Err Dif 28 Std Error uses a pooled estimate of error variano Upper CL Dif 0.8854 Lower CL Dif -27.922 Prob >t 0.4427 t Test Confidence 0.95 Prob <t 0.5573 -40 -20 0 20 B-A Assuming unequal variances 2.133 t Ratio 14.673 DF 42.677 Prob > || Difference 0.145397 Analysis of Variance Std Err Dif 27.99884 Upper CL Dif Lower CL Dif -38.411 Confidence 0.8854 Source DF Sum of Squares Mean Square FRatio Prob >F Prob >t 0.4427 Тeam 1 34.133 34.13 0.0211 0.8854 0.99 Prob <t 0.5573 Error 28 45209.333 1614.62 C. Total 29 45243.467 Means for Oneway Anova Level Number Mean Std Error Lower 95% Upper 95% A 15 253.800 10.375 232.55 275.05 15 255.933 10.375 234.68 277.19 Std Error uses a pooled estimate of error variance t Test В-А Assuming unequal variances 2.133 t Ratio 14.673 DF 32.189 Prob > |t| Difference 0.145397 Std Err Dif 27.99884 Upper CL Dif 0.8854 Lower CL Dif -27.922 Prob >t 0.4427 Confidence 0.95 Prob <t 0.5573 -40 -20 20 40 Weight II
O (a)
A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use l, - ug, where u, is
Team B and u, is Team A.)
O Hoi Hq = Hz
= 0.5
= 0.5
Ho: My = H2
O Hoi Hq> Hz
O (b)
What is the mean difference in weight (in pounds) between the two teams? (Use u, - ug, where u, is Team B and u, is Team A.)
Ibs
Which team, on average, had the higher weight?
O Team A
O Team B
O not enough information
e (c)
Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the
hypothesis test at the 99% confidence level. (Round your answers to three decimal places.)
t-statistic
critical value
p-value
B (d)
At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks.
The null hypothesis should --Select---
. The mean weights between the two teams
---Select--- V significantly different at the 99% confidence level.
Transcribed Image Text:O (a) A football statistician is interested to see if the two teams have significantly different weights. What is the hypothesis test to be done? (Use l, - ug, where u, is Team B and u, is Team A.) O Hoi Hq = Hz = 0.5 = 0.5 Ho: My = H2 O Hoi Hq> Hz O (b) What is the mean difference in weight (in pounds) between the two teams? (Use u, - ug, where u, is Team B and u, is Team A.) Ibs Which team, on average, had the higher weight? O Team A O Team B O not enough information e (c) Assume the population variances for the two samples are equal (then df = n1 + n2 - 2). Find the t-statistic, critical value, and the p-value associated with the hypothesis test at the 99% confidence level. (Round your answers to three decimal places.) t-statistic critical value p-value B (d) At a 99% confidence level, should the null hypothesis be rejected or not? Fill in the blanks. The null hypothesis should --Select--- . The mean weights between the two teams ---Select--- V significantly different at the 99% confidence level.
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