Question
Asked Dec 25, 2019
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A glass windowpane in a home is 0.62 cm thick and has dimensions of 1.0 m x 2.0 m. On a certain day, the indoor temperature is 25°C and the outdoor temperature is 0°C. (a) What is the rate at which energy is transferred by heat through the glass? (b) How much energy is lost through the window in one day, assuming the temperatures inside and outside remain constant?

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Expert Answer

Step 1

(a)

The rate of energy transferred by heat through glass is given by

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P = kA -T,)

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Step 2

Substituting the values gives

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(25.0°C-0°C) P = (0.80W/m - °C)(1.00m x 2.00m Im 0.620cm x 100cm = 6.45x10 W

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Step 3

(b)

The energy lost per day through...

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Q = Pxt

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Work,Power and Energy

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