A good curve-fit to the head vs. flow for the 32-inch pump in the image shown below is: H(inft)≈500−(2.9E−7)Q2,Qingal/minH(in⁢   ft)≈500−(2.9E−7)Q2⁢  ,    Q⁢    in⁢    gal/min⁡ Assume the same rotation rate, 1170 r/min, and estimate the flow rate this pump will provide to deliver water from a reservoir, through 900 ft of 12-inch pipe, to a point 300 ft above the reservoir surface. Assume a friction factor f = 0.019.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A good curve-fit to the head vs. flow for the 32-inch pump in the image shown below is:

H(inft)≈500−(2.9E−7)Q2,Qingal/minH(in⁢   ft)≈500−(2.9E−7)Q2⁢  ,    Q⁢    in⁢    gal/min⁡

Assume the same rotation rate, 1170 r/min, and estimate the flow rate this pump will provide to deliver water from a reservoir, through 900 ft of 12-inch pipe, to a point 300 ft above the reservoir surface. Assume a friction factor f = 0.019.

Answer in gal/min

n = 1170 r/min
50
800
NPSH
700
36금-in dia.
20
600
32-in dia.
87%
500
400
2500 bhp
28-in dia.
300
1500 bhp
200
4
8
12
16
20
24
28
U.S. gallons per minute x 1000
NPSH, ft
%88
3500 bhp
8%,
3000 bhp
%78
- 87%
%8/.
2000 bhp
Total head, ft
Transcribed Image Text:n = 1170 r/min 50 800 NPSH 700 36금-in dia. 20 600 32-in dia. 87% 500 400 2500 bhp 28-in dia. 300 1500 bhp 200 4 8 12 16 20 24 28 U.S. gallons per minute x 1000 NPSH, ft %88 3500 bhp 8%, 3000 bhp %78 - 87% %8/. 2000 bhp Total head, ft
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