A graphite heat exchanger is constructed by drilling circular channels in a solid block of graphite. Consider a large graphite block (k = 800 W/m*K) containing two 1-in. diameter channels spaced 2 in. apart (center-to-center). A highly corrosive liquid (T = 350F, h = 120 Btu/h*ft^2 *F) flows through one channel and a coolant (T = 170F, h = 200 Btu/h*ft^2 *F) flows in the other channel. Calculate the rate of heat transfer from the corrosive liquid to the coolant per foot of exchanger length. Ans. 3470 Btu/h*ft of length.

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