a) H2SEO3 + H2S Se + HSO41- (H*) b) As2S3 + CiO31- → Cl1- + H2ASO41- + S (H*) с) P > PНз + H2РО21- (ОН-) d) NO31- + BizS3 → Bi3+ + NO + S (acidic solution) e) Bi(OH)3 + Sn(OH)31- → Sn(OH)6²- + Bi (basic solution) f) MnO41- + NO21- → Mn02 + NO31- (ОН-) g) HO21- + Cr(OH)41- → Cr042- + OH1- (basic solution) h) Br1- + S042- → Br2 + SO2 (H+) i) FeO + H202 → Fe3+ + H2O (acidic solution)

Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Balance the following redox equations using the half-reaction method

a) H2SEO3 + H2S Se + HSO41-
(H*)
b) As2S3 + CiO31- → Cl1- + H2ASO41- + S
(H*)
с) P > PНз + H2РО21-
(ОН-)
d) NO31- + BizS3 → Bi3+ + NO + S
(acidic solution)
e) Bi(OH)3 + Sn(OH)31- → Sn(OH)6²- + Bi
(basic solution)
f) MnO41- + NO21- → Mn02 + NO31-
(ОН-)
g) HO21- + Cr(OH)41- → Cr042- + OH1-
(basic solution)
h) Br1- + S042- → Br2 + SO2
(H+)
i) FeO + H202 → Fe3+ + H2O
(acidic solution)
Transcribed Image Text:a) H2SEO3 + H2S Se + HSO41- (H*) b) As2S3 + CiO31- → Cl1- + H2ASO41- + S (H*) с) P > PНз + H2РО21- (ОН-) d) NO31- + BizS3 → Bi3+ + NO + S (acidic solution) e) Bi(OH)3 + Sn(OH)31- → Sn(OH)6²- + Bi (basic solution) f) MnO41- + NO21- → Mn02 + NO31- (ОН-) g) HO21- + Cr(OH)41- → Cr042- + OH1- (basic solution) h) Br1- + S042- → Br2 + SO2 (H+) i) FeO + H202 → Fe3+ + H2O (acidic solution)
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