A horizontal force, F1 = 55 N, and a force, F2 = 16.3 N acting at an angle of θ to the horizontal, are applied to a block of mass m = 2.6 kg. The coefficient of kinetic friction between the block and the surface is μk = 0.2. The block is moving to the right. Question: Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if θ = 30°. and, Solve numerically for the magnitude of acceleration of the block, a in m/s2, if θ = 30

A horizontal force, F1 = 55 N, and a force, F2 = 16.3 N acting at an angle of θ to the horizontal, are applied to a block of mass m = 2.6 kg. The coefficient of kinetic friction between the block and the surface is μk = 0.2. The block is moving to the right. Question: Solve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if θ = 30°. and, Solve numerically for the magnitude of acceleration of the block, a in m/s2, if θ = 30

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 61P

See similar textbooks

Similar questions

If the vector components of the position of a particle moving in the xy plane as a function of time are x(t)=(2.5ms2)t2i and y(t)=(5.0ms3)t3j, when is the angle between the net force on the particle and the x axis equal to 45?
The x and y coordinates of a 4.00-kg particle moving in the xy plane under the influence of a net force F are given by x = t4 6t and y = 4t2 + 1, with x and y in meters and t in seconds. What is the magnitude of the force F at t = 4.00 s?
A 3.00-kg object is moving in a plane, with its x and y coordinates given by x = 5t2 1 and y = 3t3 + 2, where x and y are in meters and t is in seconds. Find the magnitude of the net force acting on this object at t = 2.00 s.
In Fig, a slab of mass m1 =40 kg rests on a frictionless floor, and a block of mass m2 =10kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force of magnitude 100 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
In the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
A particle, which remains at rest, is acted on by three forces F, G and H. The force F has magnitude 16N and is directed to the right and down, making an angle of 50 degrees with the horizontal. The force G has magnitude 7N and is directed to the left and down, making an angle of 50 degrees with the horizontal. Find the magnitude of the vector H, and the acute angle it makes with the horizontal. Give the magnitude to one decimal place and the angle to the nearest degree. What is the magnitude of H and what is the acute angle H makes with the horizon?
a slab of mass m1 40 kg rests on a frictionless floor, and a block of mass m2 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40.A horizontal force of magnitude 100 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
the coefficient of static friction between block A and a horizontal floor is 0.320, and the coefficient of static friction between block B and the floor is 0.300. The mass of each block is 2.00kg,and they are connected together by a cord. If a horizontal force F pulling on block B is slowly increased ,in a direction parallel to the connectin cord,until the block start sliding ,what is the magnitude of F at the instant that they start to slide?
There are two forces on the 1.19 kg box in the overhead view of the figure but only one is shown. For F1 = 15.7 N, a = 14.7 m/s2, and θ = 34.1°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
A block with mass m1 = 9.2 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μk = 0.58. A second block with a mass m2 = 10.8 kg is connected to the first by an ideal string passing over an ideal pulley such that the second block is suspended vertically. The second block is released from rest, and motion occurs. Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, ΣFy, for block 2. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction, ΣFx for block 1. Block 1 accelerates along the tabletop, in the horizontal direction, while block 2 moves vertically. With the coordinate system provided in the drawing, we may write a⃗ 1=a1i^a→1=a1i^ and a⃗ 2=a2y^a→2=a2y^. Write an expression that relates the vertical component of the acceleration of block 2 to the horizontal component of the acceleration of block 1. Write an expression using the…
A block with mass m1 = 9.2 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μk = 0.58. A second block with a mass m2 = 10.8 kg is connected to the first by an ideal string passing over an ideal pulley such that the second block is suspended vertically. The second block is released from rest, and motion occurs. Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, ΣFy, for block 2. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction, ΣFx for block 1. Block 1 accelerates along the tabletop, in the horizontal direction, while block 2 moves vertically. With the coordinate system provided in the drawing, we may write a⃗ 1=a1i^a→1=a1i^ and a⃗ 2=a2y^a→2=a2y^. Write an expression that relates the vertical component of the acceleration of block 2 to the horizontal component of the acceleration of block 1. Write an expression using the…
A 3.5 kg particle moves along an x axis according to x(t) = −12 + 5t2 − 4t3, with xin meters and t in seconds. In unit-vector notation, what is the net force acting on theparticle at t = 6 s?