a httpssession masteringengineering.com/myct/itemViewhoftset next8iassignmertProblem/D-8226925 ← → 自 KHomework 4 Problem 13.86 9 of 14 (> - Part A magnitude of the resultant force acting on a 8:5 kg paricte at the instant 2s t the partile is moving along a horizontaf path defined by Express your answer with the appropriate units. PaeUis FValue Request Answer Provide Feedback Ned > O Type here to search ESC Home End Del FO 10 #12

The wind has deposited sand on a platform so that the intensity of the load isapproximately w = 0.5x^3 N / m. simplify the distributed load to a resulting force and specify its magnitude and location from A.

Engineering Mechanics IIThe chipping machine is designed to eject wood chips at Vo = 4.57 m/s. If the tube is oriented at 15 degrees from the horizontal, determine how high, h (in ft), the chips strike the pile if at this instant they landed on the pile 457. 3 cm from the tube.   you can download the book we are using through this link :https://drive.google.com/file/d/1Ws-HdkaO4OAfTMa1crhsf63rbClZUCl5/view?usp=sharing

The particle  in the box exercise 21 is in its ground state of nx=ny=nz=1. a) find the probability that the particle will be found in the volume defined by 0<x>L/4, 0<y>L/4, 0<z>L/4. b) Do the same for L/2 instead of L/4.                 ,

A car of mass 250 kg starts at B with initial velocity 50.4 m/s for h=45 m, radius of curvature at C is ρ =25 m. The car barely reaches point D.speed at C (m/s) a. 40.720510802297 b. 48.864612962757 c. 57.008715123216 d. 65.152817283675 e. 32.576408641838Normal at C (m/s) a. 16957.92 b. 14131.6 c. 19784.24 d. 22610.56 e. 11305.28H (m)?

A particle of mass 133 kg is traveling on a constant radius 1.1 m with a angle of 0.23*sin(0.35t). 1. What is the transverse speed at 2.6 seconds? [m.s-1] 2. What is the radial force at 2.6 seconds? [N] 3. What is the transverse force on the particle at 2.6 seconds? [N

A constant force acting on a particle can be expressed in Cartesian vector form as F = 3i + Sj - 4k N. Determine the work done by the force on the particle if the displacement of the particle can be expressed in Cartesian vector form as s = 4i - 2j + 3k m.

13.12 Fluid A is found to have a surface tension of 0.080 N m−1, a density of 1.2 × 103 kg m−3 and a contact angle of 70° with dry glass. Fluid B is found to have a surface tension of 0.100 N m−1, a density of 3.1 × 103 kg m−3 and a contact angle of 110° with dry glass. A glass capillary tube with an inner radius 1 mm is lowered into a container of fluid A and an identical capillary tube is lowered into a flask of fluid B. To what height above (or below) the fluid surface will fluids A and B rise in their respective capillary tubes?

To use the concept of conservation of energy on a system of particles to determine key characteristics about the mechanics of the system, such as velocity and position. The 3.45 kg cols lar hown below is attached dto a spring an released from rest at A. The collar then travels downward a distance of y = 1.90 m . The spring has a spring constant of k = 22.5 N/m . The distance a is given as 1.10 m. The datum for gravitational potential energy is set at the horizontal line through A and B.                                                                                                                           Determine the magnitude of the velocity of the collar at C when the effects of friction are neglected. The spring is initially unstretched when the collar is at A. Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at C is 3.66 m/s . The spring is initially unstretched when the collar is at A. Determine the magnitude of the…

A two degrees of freedom mass spring system is fixed at one end, where independent masses can move only in the vertical direction. Considering the system as finite elements, determine the vertical displacement for each mass. Also draw the free body diagram of this system. Use 'X' KN/m as the stiffness value for all the springs and 'Y' Kg as the value for all masses. Where, 'X'= (63) 'Y'= (93)