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A human resources manager for a company had a choice of how to administer an aptitude test for employee recruits. The New form of the test was administered via computer. The Old form had the same content, but was delivered via paper and pencil. The manager wanted to know if the tests were equivalent in terms of mean scores. If they were equivalent, the manager could give the test by either method, but if they were not equivalent, the manager would have to stick with one administration method in order to be fair to all recruits taking the test. The manager formed his hypotheses, and set an alpha level of .05. The results of a hypothesis test using the two administration methods is shown below. What should the manager do? t-Test: Two-Sample Assuming Equal Variances New Old Mean 15 11.1 13.33333 18.76667 Variance Observations 10 10 Pooled Variance 16.05 Hypothesized Mean Difference df 18 t Stat 2.176768 P(T<=t) one-tail t Critical one-tail 0.021526 1.734064 P(T<=t) two-tail t Critical two-tail 0.043053 2.100922 Select one: a. Use only one form, because the means are different. That's all you need to know. b. Use one form, because the p-level for a one-tailed test is .021 which is smaller than .05 c. Use only one method because the p-level for a two-tailed test is .043 which is less than .05 d. Use either method because the p-level for a two-tailed test is less than .05, which indicates that the tests are eguivalent

A human resources manager for a company had a choice of how to administer an aptitude test for employee recruits. The New form of the test was administered via computer. The Old form had the same content, but was delivered via paper and pencil. The manager wanted to know if the tests were equivalent in terms of mean scores. If they were equivalent, the manager could give the test by either method, but if they were not equivalent, the manager would have to stick with one administration method in order to be fair to all recruits taking the test. The manager formed his hypotheses, and set an alpha level of .05. The results of a hypothesis test using the two administration methods is shown below. What should the manager do? t-Test: Two-Sample Assuming Equal Variances New Old Mean 15 11.1 13.33333 18.76667 Variance Observations 10 10 Pooled Variance 16.05 Hypothesized Mean Difference df 18 t Stat 2.176768 P(T<=t) one-tail t Critical one-tail 0.021526 1.734064 P(T<=t) two-tail t Critical two-tail 0.043053 2.100922 Select one: a. Use only one form, because the means are different. That's all you need to know. b. Use one form, because the p-level for a one-tailed test is .021 which is smaller than .05 c. Use only one method because the p-level for a two-tailed test is .043 which is less than .05 d. Use either method because the p-level for a two-tailed test is less than .05, which indicates that the tests are eguivalent

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 10CYU
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A human resources manager for a company had a choice of how to administer an aptitude test for employee recruits. The New form of the test was administered via computer. The Old form had the same content, but was delivered via paper and pencil. The manager wanted to know if the tests were equivalent in terms of mean scores. If they were equivalent, the manager could give the test by either method, but if they were not equivalent, the manager would have to stick with one administration method in order to be fair to all recruits taking the test. The manager formed his hypotheses, and set an alpha level of .05. The results of a hypothesis test using the two administration methods is shown below. What should the manager do? t-Test: Two-Sample Assuming Equal Variances New Old Mean 15 11.1 13.33333 18.76667 Variance Observations 10 10 Pooled Variance 16.05 Hypothesized Mean Difference df 18 t Stat 2.176768 P(T<=t) one-tail t Critical one-tail 0.021526 1.734064 P(T<=t) two-tail t Critical two-tail 0.043053 2.100922 Select one: a. Use only one form, because the means are different. That's all you need to know. b. Use one form, because the p-level for a one-tailed test is .021 which is smaller than .05 c. Use only one method because the p-level for a two-tailed test is .043 which is less than .05 d. Use either method because the p-level for a two-tailed test is less than .05, which indicates that the tests are eguivalent
Transcribed Image Text:A human resources manager for a company had a choice of how to administer an aptitude test for employee recruits. The New form of the test was administered via computer. The Old form had the same content, but was delivered via paper and pencil. The manager wanted to know if the tests were equivalent in terms of mean scores. If they were equivalent, the manager could give the test by either method, but if they were not equivalent, the manager would have to stick with one administration method in order to be fair to all recruits taking the test. The manager formed his hypotheses, and set an alpha level of .05. The results of a hypothesis test using the two administration methods is shown below. What should the manager do? t-Test: Two-Sample Assuming Equal Variances New Old Mean 15 11.1 13.33333 18.76667 Variance Observations 10 10 Pooled Variance 16.05 Hypothesized Mean Difference df 18 t Stat 2.176768 P(T<=t) one-tail t Critical one-tail 0.021526 1.734064 P(T<=t) two-tail t Critical two-tail 0.043053 2.100922 Select one: a. Use only one form, because the means are different. That's all you need to know. b. Use one form, because the p-level for a one-tailed test is .021 which is smaller than .05 c. Use only one method because the p-level for a two-tailed test is .043 which is less than .05 d. Use either method because the p-level for a two-tailed test is less than .05, which indicates that the tests are eguivalent
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